2016-05-24 03:01:15 +02:00
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// Copyright 2016 Google Inc. Use of this source code is governed by an
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// MIT-style license that can be found in the LICENSE file or at
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// https://opensource.org/licenses/MIT.
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2016-05-24 23:01:41 +02:00
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import 'dart:collection';
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2016-08-05 02:25:57 +02:00
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import 'dart:math' as math;
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2016-05-24 23:01:41 +02:00
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2016-06-06 08:51:50 +02:00
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import 'package:charcode/charcode.dart';
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2016-08-13 00:24:27 +02:00
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import 'package:collection/collection.dart';
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2016-05-24 03:01:15 +02:00
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import 'package:source_span/source_span.dart';
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import 'ast/node.dart';
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2016-06-03 22:36:20 +02:00
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import 'value/number.dart';
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2016-06-04 01:31:29 +02:00
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const _epsilon = 1 / (10 * SassNumber.precision);
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2016-05-24 03:01:15 +02:00
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2016-06-10 02:55:04 +02:00
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class LinkedListValue<T> extends LinkedListEntry<LinkedListValue<T>> {
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final T value;
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LinkedListValue(this.value);
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}
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2016-08-15 07:32:00 +02:00
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/// A pair of values.
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class Pair<E, F> {
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final E first;
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final F last;
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Pair(this.first, this.last);
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String toString() => '($first, $last)';
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bool operator==(other) {
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if (other is! Pair) return false;
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return other.first == first && other.last == last;
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}
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int get hashCode => first.hashCode ^ last.hashCode;
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}
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2016-08-13 00:24:27 +02:00
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bool listEquals/*<T>*/(List/*<T>*/ list1, List/*<T>*/ list2) =>
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const ListEquality().equals(list1, list2);
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2016-08-13 01:53:19 +02:00
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int listHash(List list) => const ListEquality().hash(list);
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2016-06-06 09:05:04 +02:00
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FileSpan spanForList(List<AstNode> nodes) {
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2016-05-24 03:01:15 +02:00
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if (nodes.isEmpty) return null;
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return nodes.first.span.expand(nodes.last.span);
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}
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2016-05-24 23:01:41 +02:00
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2016-06-06 08:51:50 +02:00
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String unvendor(String name) {
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assert(!name.isEmpty);
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if (name.codeUnitAt(0) == $dash) return name;
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for (var i = 1; i < name.length; i++) {
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if (name.codeUnitAt(0) == $dash) return name.substring(i + 1);
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}
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return name;
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}
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2016-06-10 02:55:04 +02:00
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bool equalsIgnoreCase(String string1, String string2) {
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if (string1 == null) return string2 == null;
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if (string2 == null) return false;
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if (string1.length != string2.length) return false;
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return string1.toUpperCase() == string2.toUpperCase();
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2016-05-24 23:01:41 +02:00
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}
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2016-06-03 22:36:20 +02:00
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bool almostEquals(num number1, num number2) =>
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(number1 - number2).abs() < _epsilon;
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2016-06-10 02:55:04 +02:00
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2016-08-02 20:36:34 +02:00
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List/*<T>*/ longestCommonSubsequence/*<T>*/(List/*<T>*/ list1,
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List/*<T>*/ list2, {/*=T*/ select(/*=T*/ element1, /*=T*/ element2)}) {
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select ??= (element1, element2) => element1 == element2 ? element1 : null;
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var lengths = new List.generate(
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list1.length + 1, (_) => new List.filled(list2.length + 1, 0),
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growable: false);
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2016-08-15 05:19:27 +02:00
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var selections = new List<List/*<T>*/>.generate(
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2016-08-02 20:36:34 +02:00
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list1.length, (_) => new List/*<T>*/(list2.length),
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growable: false);
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// TODO(nweiz): Calling [select] here may be expensive. Can we use a memoizing
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// approach to avoid calling it O(n*m) times in most cases?
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for (var i = 0; i < list1.length; i++) {
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for (var j = 0; j < list2.length; j++) {
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var selection = select(list1[i], list2[j]);
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selections[i][j] = selection;
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lengths[i + 1][j + 1] = selection == null
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? math.max(lengths[i + 1][j], lengths[i][j + 1])
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: lengths[i][j] + 1;
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}
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}
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List/*<T>*/ backtrack(int i, int j) {
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if (i == -1 || j == -1) return [];
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var selection = selections[i][j];
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if (selection != null) return backtrack(i - 1, j - 1)..add(selection);
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return lengths[i + 1][j] > lengths[i][j + 1]
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? backtrack(i, j - 1)
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: backtrack(i - 1, j);
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}
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return backtrack(list1.length - 1, list2.length - 1);
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}
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