--TEST--
DESSA 003
--TARGET--
x86
--ARGS--
-S
--CODE--
# Figure 8 (swap problem) from "Translating Out of Static Single Assignment Form" by Sreedhar
{
	uintptr_t c_1 = 0;
	bool c_2 = 0;
	bool c_3 = 1;
	int32_t c_4 = 1;
	int32_t c_12 = 12;
	l_1 = START(l_13);
	int32_t x0 = PARAM(l_1, "x", 0);
	int32_t y1 = PARAM(l_1, "y", 1);
	int32_t cond = PARAM(l_1, "z", 2);
	int32_t x1 = DIV(x0, c_12);
	l_3 = END(l_1);
	l_4 = LOOP_BEGIN(l_3, l_9);
	int32_t x2 = PHI(l_4, x1, x3);
	int32_t y2 = PHI(l_4, y1, y3);
	int32_t z = COPY(x2);
	int32_t x3 = COPY(y2);
	int32_t y3 = COPY(z);
	l_7 = IF(l_4, cond);
	l_8 = IF_TRUE(l_7);
	l_9 = LOOP_END(l_8, l_4);
	l_10 = IF_FALSE(l_7);
	l_13 = RETURN(l_10, z);
}
--EXPECT--
test:
	subl $8, %esp
	movl %ebx, 4(%esp)
	movl %ebp, (%esp)
	movl 0x10(%esp), %ecx
	movl 0x14(%esp), %ebx
	movl 0xc(%esp), %eax
	movl $0xc, %ebp
	cltd
	idivl %ebp
.L1:
	testl %ebx, %ebx
	je .L2
	movl %eax, %edx
	movl %ecx, %eax
	movl %edx, %ecx
	jmp .L1
.L2:
	movl 4(%esp), %ebx
	movl (%esp), %ebp
	addl $8, %esp
	retl